Math, asked by monuverma9941, 10 months ago

A train has a length of 150150 meters It is passing a man Who is moving at 22km/hr in the same direction of the train in 3 seconds find out the speed of the train

Answers

Answered by gautamkumar118
2

Step-by-step explanation:

 Length \:of\: train\:= \:150 m\\ \\</p><p>Speed\: of\: train \:=\: s \\ \\</p><p>Speed \:of \:man \:= \:22\:km/hr\: = \: 22 × \frac{5} {18}\: m/s\: = \: \frac{55} {9} \:m/s\\ \\</p><p>Time\:take \:to\: Pass\:he \:train\: to \:man \:= \:3 sec\\ \\ \:Relative \:speed \:= \:s-55/9\\ \\</p><p>Then,  \\</p><p>\blue{\bold{Time\: taken\: to\:pass\: the\:man\:= \: \frac{distance} {Relative\: speed}}} \\  </p><p>      \implies{3\:= \: \frac{150} {s- \frac{55} {9}}} \\       </p><p>   \implies{3(s- \frac{55} {9} ) \:=\: 150} \\    </p><p>     \implies{3s -  \frac{55} {3} \:=\: 150} \\         </p><p>  \implies{3s\: =\: \frac{150+55} {3}} \\           \implies{3s \:=\:  \frac{750+55} {3}} \\          \implies{3s \:= \: \frac{805} {3}} \\          \implies{ S \:= \: \frac{805}{9} \:m/s} \\               \implies{\: \: \: \: \:=\:  322   \:km/hr} \\ \\ \\ \\   \pink{\bold{I \:hope\: you\: like \:it\: and \:mark\: brainliest \:answer.}}

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