A train has a speed of 60km/h. For the first one hour and 40km/h for the next half hour. Its average speed in km/h
Answers
Given:
Speed = 60km/h
First four = 40km/h
Explanation:
train has a speed of 60km/h for the first one hour,
t₁ =1hr, v₁=60km/hr
Distance covered by the train, d₁ =v₁t₁
d₁ = 60×1 km
For the next half hour, train has speed 40km/hr
v₂ =40km/hr, t₂ =0.5hr
d₂ = v₂t₂
d₂ =40×0.5=20km
Total distance, d= d₁ + d₂
d=60+20=80km
Total time, t = t₁ + t₂
t=1hr+0.5hr=1.5hr
Average speed, v(avg) = d/t
v(avg) = 80km/1.5hr
=53.33km/h
Answer = 53.33k/h
Given,
The speed of a train for the first one hour = 60 km/hr
The speed of a train for the next half hour = 40 km/hr
To find,
The average speed of the train in km/hr.
Solution,
We can simply solve this mathematical problem using the following process:
Mathematically,
Speed = distance covered/time taken
=> distance covered = speed × time taken
{Equation-1}
Now, for the first one hour,
speed of the train = 60 km/hr
So, the total distance covered in the first one hour
= speed × time taken
(according to equation-1)
= 60 km/hr × 1 hr = 60 Km
Now, for the next half hour,
speed of the train = 40 km/hr
So, the total distance covered in the next half hour
= speed × time taken
(according to equation-1)
= 40 km/hr × 1/2 hr = 20 Km
Now, for the entire 1.5 hrs journey,
total distance covered
= total distance covered in the first one hour + total distance covered in the next half hour
= 60 Km + 20 Km
= 80 Km
So, the average speed of the train
= total distance covered/total time taken
= 80 Km/1.5 hrs
= 53.3 Km/hr
Hence, the average speed of the train is equal to 53.3 Km/hr.