Question

A train has a velocity of 10m/s, it now accelerate at 1m/s² for ¹/4 min. Find the distance traveled in this time and the average speed

Answer 1

Answer:

Thus the final sped of the car will be 130m/s and the distance covered is 2100 m

Explanation:

v=u+atv=u+at

v=10m/s+4m/s2∗30sv=10m/s+4m/s2∗30s

v=10m/s+120m/sv=10m/s+120m/s

v=130m/sv=130m/s

For distance, use:

s=ut+1/2at2s=ut+1/2at2

s=10m/s∗30s+1/2∗4m/s2∗(30s)2s=10m/s∗30s+1/2∗4m/s2∗(30s)2

s=300m+2m/s2∗900s2s=300m+2m/s2∗900s2

s=300m+1800ms=300m+1800m

s=2100ms=2100m

Thus the final sped of the car will be 130m/s and the distance covered is 2100 m

Answer 2

Answer:

This is the answer. It is an application of newton's equations.