a train has to negotiate a curve of 400m radius . by how much should the outer Railway raised with respect to in Israel for a speed of 48 km per hour ? the distance between the rails is 1 m.
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radius of curved path is r. width of path is b m. the outer edge is raised by h w.r.t inner edge so that a car with speed v can pass safe over it.
the value of h is
tanθ = v²/rg=h/bh
=v ²b/rg substituting the values according to given question,
v=48km/h =(48x 1000)/60x60m/s⇒40/3
m/sb=1
mr=400mg=9.8m/s2h=(40/3)²x1/400x9.8
⇒0.0045m
∴⇒4.54cm Ans
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Answer:0.04m
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