A train has travelled 734 kilometre 500 metre towards its destination which is 1200 kilometre 750 metres away.find the distance that remains.
Answers
Answer:
Answer:
The original speed of the train is 30 km/hr.
Step-by-step explanation:
Given: A train travelling a distance of 1200 km at a constant speed when the driver learnt that he was running late, he increased the speed by 5 km/h. Now the journey took 8 hrs less than and reached on time.
To find The original speed of the train.
Solution :
Let the consonant speed s and time t
\text{Speed}=\frac{\text{Distance}}{\text{Time}}Speed=
Time
Distance
A train travelling a distance of 1200 km at a constant speed when the driver learnt that he was running late.
s=\frac{1200}{t}s=
t
1200
.....[1]
He increased the speed by 5 km/h and the journey took 8 hrs less than and reached on time.
s+5=\frac{1200}{t-8}s+5=
t−8
1200
.......[2]
From [1] and [2]
\frac{1200}{t}=\frac{1200}{t-8}-5
t
1200
=
t−8
1200
−5
\frac{1200}{t-8}-\frac{1200}{t}=5
t−8
1200
−
t
1200
=5
\frac{1200t-1200t+9600}{t(t-8)}=5
t(t−8)
1200t−1200t+9600
=5
\frac{9600}{t^2-8t}=5
t
2
−8t
9600
=5
5t^2-40t=96005t
2
−40t=9600
t^2-8t-1920=0t
2
−8t−1920=0
t^2-48t+40t-1920=0t
2
−48t+40t−1920=0
t(t-48)+40(t-48)=0t(t−48)+40(t−48)=0
(t-40)(t-48)=0(t−40)(t−48)=0
t=40 , t=-48t=40,t=−48
We neglect t=-48
So, The time is t=40
Substitute in [1]
s=\frac{1200}{40}s=
40
1200
[tex]s=30/tex]
The original speed of the train is 30 km/hr.
Answer:
Total Distance =1200 km 750 m
Travelled =734km 500 m
Distance to be travelled =1200 km 750 m -734 km 500 m = 450234
So the distance remains =450234