Question

A Train Have 30 container and speed of train is 120km/h if we apply break of 20 Newton what is the speed of Train ​

Answer 1

Answer:

Velocity of moving vehicle=v

0

and decceleration =a

Final velocity of the vehicale =0 (As it stops)

Let the stopping distance be s

Then applying the third equation of motion we have:

v

2

=v

0

2

+2(−a)s

⇒0=v

0

2

−2as

⇒s=

2a

v

0

2

→ Expression for stopping distance.