Question

A train increases its speed steadily from 10m/s to 20m/s in 1minute. How far does it travel while increasing its speed?

Answer 1

Answer:

930 metres.

Explanation:

Here the speed is increasing steadily.

so in 1 minute the speed is increasing 10 times. So speed is increasing by 1m/s in every 6 seconds.

so,

6 × 11 = 66

6× 12 = 72

6 × 13 = 78

6 × 14 = 84

6 × 15 = 90

6 × 16 = 96

6 × 17 = 102

6 × 18 = 108

6 × 19 = 114

6 × 20 = 120

Total = 960.

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Answer 2

Answer:

The distance travelled by train $=900m.$

Explanation:

• Given,

Initial speed of train $u = 10m/s$

Final speed of train $v = 20m/s$

Time taken by train to attain speed $t = 1minute$

                                                           $t = 60seconds$

• To calculate the value of acceleration,

By using first equation of motion, we get

     $v - u = at$                                (where a is the acceleration of the train)

  $20-10 = 60a$

       $\frac{10}{60} = a$

  $a =\frac{10}{60}m/s$

   $a = \frac{1}{6} m/s$

• To calculate the value of distance travelled, we get

Using third equation of motion,

$v^{2} -u^{2} = 2as$                       (where s is the distance travelled by the car)

$20^{2} -10^{2} =2*s *\frac{1}{6}$

we know that,

$20^{2} = 20*20 = 400$ and $10^{2} = 10* 10 = 100$

$400 -100 = 2 *s*\frac{1}{6}$            

        $300 = \frac{1}{3} s$

$s = 900metres$

Therefore, the train travels $s= 900metres$ while increasing its speed.

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