Question

A train, initially moving at 12 m/s, speeds up
to 36 m/s in 120 s. What is its acceleration?​

Answer 1

Answer:

0.12 ms^-2

Explanation:

u = 12 m/s

v = 36 m/s

t = 120 s

a = ?

v = u + at

36 = 12 + 120a

24 = 120a

a = 24/120

a = 0.12 ms^-2