Question

a train is 180 m long it is running at a speed of 50 km per hour how much time will it take to pass a platform 220 m long​

Answer 1

Step-by-step explanation:

As given

Speed of train (v)=45Km/h(v)=45Km/h

Length of train (l)=180m(l)=180m

Length of tunnel (L)=540m(L)=540m

If train enters in tunnel when it's engine enters in tunnel and leaves it when it's last Wagon leaves the tunnel.

In this way train cover Distance equals to sum of length of tunnel and train.

So Distance Covered (s)=L+l(s)=L+l

s=540m+180ms=540m+180m

s=720ms=720m

s=0.720Kms=0.720Km ( As we know that 1Km=1000m1Km=1000m )

As we know that

Speed(v)=Distance(s)Time(t)Speed(v)=Distance(s)Time(t)

Now putting these values we get

45Km/h=0.720Kmt45Km/h=0.720Kmt

t=0.720Km45Km/ht=0.720Km45Km/h

t=0.016ht=0.016h

t=0.016×60×60seconds(1h=3600sec)t=0.016×60×60seconds(1h=3600sec)

t=57.6secondt=57.6second

Time taken by train is 57.6 seconds

Answer 2

Answer:

As given

Speed of train (v)=45Km/h

Length of train (l)=180m

Length of tunnel (L)=540m

If train enters in tunnel when it's engine enters in tunnel and leaves it when it's last Wagon leaves the tunnel.

In this way train cover Distance equals to sum of length of tunnel and train.

So Distance Covered (s)=L+l

s=540m+180m

s=720m

s=0.720Km ( As we know that 1Km=1000m )

As we know that

Speed(v)=Distance(s)Time(t)

Now putting these values we get

45Km/h=0.720Kmt

t=0.720Km45Km/h

t=0.016h

t=0.016×60×60seconds(1h=3600sec)

t=57.6second

Time taken by train is 57.6 seconds

Step-by-step explanation:

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