Question

A train is accelerated from 20km/hr to 80km/hr in 4 minutes. Plot its v-t graph. Calculate its acceleration. How much distance does it cover in this period? Assume that the tracks are straight

Answer 1

Answer:

Hlo here is your answer....

Explanation:

Here,

Initial velocity(u) = 20 km/hr

final velocity (v) = 80km/hr

time take (t) = 4/60 hr

= 1/15 hr

Distance(s )= ?

so firstly we have to find acceleration

Acceleration(a) = (v - u)/t

= ( 80-20)/1/15

= 60× 15

= 900 km/hr ^2

Now by using formula

v^2 = u^2 + 2as

(80)^2 = (20)^2 + 2× 900×s

6400 = 400 + 1800 × s

6400-400/1800 = s

6000/1800 = s

60/18 = s

10/3 = s

3.33 = s

s= 3.33 km is your answer

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