A train is approaching a tunnel pq. A cat is seen at a point inside the tunnel pq, at a distance, which is 2/7 of the length of pq from p. If the cat moves towards the train, the train will meet the cat at the entrance of tunnel i.E. P. If the cat moves away from the train, the train meets the cat at the exit of the tunnel i.E. Q. Find the ratio of the speeds of the cat and the train.
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Very easy. If it goes 33 parts towards entrance, train will catch at entrance. If 55 towards exit, then train will catch at exit.
So, difference 5−3=25−3=2 parts covered by cat =8=8 parts covered by train.
So, ratio =8:2=4:1=8:2=4:1
Note: You are thinking why 5−35−3 bcoz cat makes only 22 parts difference(5-3=2) at the time train covers full part(means 88 part). If it goes 33 toward entrance 55 towards exit just making 22 difference, means 22 parts movement in same time of full part covered by train.
So, difference 5−3=25−3=2 parts covered by cat =8=8 parts covered by train.
So, ratio =8:2=4:1=8:2=4:1
Note: You are thinking why 5−35−3 bcoz cat makes only 22 parts difference(5-3=2) at the time train covers full part(means 88 part). If it goes 33 toward entrance 55 towards exit just making 22 difference, means 22 parts movement in same time of full part covered by train.
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