a train is at a speed of 90 km per hour. Brakes are applied to produce a uniform acceleration of -0.5m/s². find how far train will go before it goes to rest
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Ans. is 625 m or 0.625 Km ... solution is in the pic :)
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given
u =90km/h ----m/sec
u=90×5/18=25m/sec
v=0
a=-0.5
now
v2=u2+2as
(0)2=(25)2+2×-0.5×s
0=625-s
s=625m
u =90km/h ----m/sec
u=90×5/18=25m/sec
v=0
a=-0.5
now
v2=u2+2as
(0)2=(25)2+2×-0.5×s
0=625-s
s=625m
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