Question

A train is at rest in a railway station at time t =0 the train starts to move forward with an increasing speed unit it reaches its maximum speed at time t =48s

Answer 1

Answer:

thanks for asking

Explanation:

Given: t=10 min=10×60=600s

Initial speed of train is given as: u=0 ms

−1

Final speed of train is given as: v=40 km h

−1

=

3600

40×1000

=11.1 ms

−1

Now acceleration is given by the relation:

a=

t

v−u

=

600

11.1−0

=0.0185 ms

−2

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