A train is at rest in a railway station at time t =0 the train starts to move forward with an increasing speed unit it reaches its maximum speed at time t =48s
Answers
Answered by
0
Answer:
Given: t=10 min=10×60=600s
Initial speed of train is given as: u=0 ms
−1
Final speed of train is given as: v=40 km h
−1
=
3600
40×1000
=11.1 ms
−1
Now acceleration is given by the relation:
a=
t
v−u
=
600
11.1−0
=0.0185 ms
−2
Similar questions