Question

A train is going at 1/3 of its usual speed and it takes an extra 30 min to reach its destination. find its usual time to cover the same distance​

Answer 1

Answer:

it takes 45 min to cover the distance

Answer 2

Its usual time to cover the same distance is 15 minutes.

Step-by-step explanation:

Required Formula:

• Time = Distance / Speed

Let's assume

The usual speed of the train be "s" km/hr

The distance travelled by the train be "D" km.

The usual time taken by the train to cover the same distance be "t" hr = D/s

Given that,

The reduced speed of the train = $\frac{s}{3}$ km/hr

Therefore, according to the question, we can write the eq.

$\frac{D}{\frac{s}{3}}$ - $\frac{D}{s} = \frac{30}{60}$

$\frac{3D}{s} - \frac{D}{s} = \frac{1}{2} \\\ \frac{D}{s} [3 - 1] = \frac{1}{2} \\\frac{D}{s} = \frac{1}{2} * \frac{1}{2} \\\frac{D}{s} = \frac{1}{4} hr$

Thus,

The usual time "t" taken by the to cover the same distance is,

= $\frac{D}{s}$

= $\frac{1}{4} * 60 minutes$

= 15 minutes

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