Question

A train is moving along a straight path with a uniform acceleration.its engine passes a pole with a velocity of 60 km/ h and the end passes across the same pole with a velocity of 80 km/ h. The middle point of the train will pass the same pole with a velocity?

Answer 1

Answer:

for this sum

u = 60km/hr

and v = 80km/hr

in middle point of post the velocity is

$= \sqrt{ \frac{ {u}^{2} + {v}^{2} }{2 } } \\ = \sqrt{ \frac{ {60}^{2} + {80}^{2} }{2} } \\ = \sqrt{ \frac{3600 + 6400}{2} } \\ = \sqrt{ \frac{10000}{2} } \\ = \sqrt{5000} \\ = 10 \times 5 \sqrt{2} \\ =50 \times 1.414 \\ = 70.71$

Ans: 70.71km/hr

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