A train is moving along a straight section of a track with a velocity of 180km/hr. The braking acceleration is 2m/s2. At what distance from a train station should the train driver apply the brake so that the train stops at the station
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First convert 180km/hr into m/s
180 x 5/18
= 50m/s
Now , we know that v = u + at
0 = 50 + 2t
-50 = 2t
t = -50/2 = -25 = 25 seconds
We know that s = ut +
s = (50)(25) + 1/2
= 1250 + 1/2
= 1250 + 1250
= 2500m
Mark as brainliest as I spent a lot of time and effort doing this while I should have been doing my project :)
180 x 5/18
= 50m/s
Now , we know that v = u + at
0 = 50 + 2t
-50 = 2t
t = -50/2 = -25 = 25 seconds
We know that s = ut +
s = (50)(25) + 1/2
= 1250 + 1/2
= 1250 + 1250
= 2500m
Mark as brainliest as I spent a lot of time and effort doing this while I should have been doing my project :)
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