Question

A train is moving at a rate of 36km/h .whenthe brakes are applied it comes to rest at 200 m calculate retardation

Answer 1

Hii..
Here is your answer..

Solution:-
Initial velocity(u)= 36km/h
To convert it in m/s we'll multiple it by 5/18
$= >3 6 \times \frac{5}{18} \\ = > 10m \: per \: sec$
Final velocity(v) =0m/s
Distance(s) =200m

We'll find the Acceleration by using equation:-
$= > {v}^{2} = {u}^{2} + 2as \\ = > {(0)}^{2} = {(10)}^{2} + 2 \times a \times 200 \\ = > - 400a = 100 \\ = > a = \frac{ - 100}{400}$
$= > a = - 0.25$
Hence,
Retardation =0.25m/s ^2

Hope it helps uh...✌️✌️✌️