Question

a train is moving at a speed of 40 km/h at 10:00 am and at 50 km/h at 10:15 am. Assuming that the train moves along a straight track and the acceleration is constant, find out the value of the acceleration

Answer 1

i think this is enough to understand

Answer 2

Concept:

Speed is the rate at which an object changes its position over time or per unit of time.

Given:

The initial velocity of the train is $40km/h$ .

The final velocity of the train is $50km/h$.

Find:

The acceleration of the train.

Solution:

Initial velocity at $10 a.m.$, $u=40km/h$ .

Final velocity at $10:15a.m.$, $v=50km/h$ .

The time taken by the train for acceleration is, $t=15min=0.25h$ .

Using the first equation of motion,

$v=u+at\\a=\frac{v-u}{t}$

$a=\frac{50-40}{0.25}$

$a=40kmp/h^2$

The acceleration of the train is $40kmp/h^2$.

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