Question

a train is moving at a speed of 40km/h at 10:00am and at 50km/h at 10:15am . Assuming that the train moves along a straight track and the acceleration is constant . find out the value of the acceleration​

Answer 1

Answer:

calculation

Explanation:

Here, u = 40 km = 40000 m

v= 50km= 50000 m

t = 15 min = 900 second

Now, a = v - u / t

= 50000 - 40000 / 900

= 10000 / 900

= 11.11 m/s²

Hope its help you

If, your answer is in km/ h then you only have to change 15 min in h. Rest all is same

Answer 2

Given :

➳ Initial speed = 40kmph

➳ Final speed = 50kmph

➳ Time of journey = 15min = 1/4h

To Find :

⟶ Acceleration of train.

SoluTion :

⇒ Acceleration is definef as the rate of change of speed.

⇒ It is a vector quantity having both magnitude as well as direction.

⇒ It can be positive, negative or zero.

⇒ SI unit : m/s²

✴ First equation of kinematics :

$\bigstar\:\underline{\boxed{\bf{v=u+at}}}$

• v denotes final speed
• u denotes initial speed
• a denotes acceleration
• t denotes time

Calculation :

$:\implies\tt\:v=u+at$

$:\implies\tt\:50=40+(a\times \frac{1}{4})$

$:\implies\tt\:50-40=\dfrac{a}{4}$

$:\implies\tt\:t=10\times 4$

$:\implies\underline{\boxed{\bf{a=40\:kmh^{-2}}}}$