Question

a train is moving at a speed of 50m/s and reduces it's speed to 10m/s by covering a distance of 240m then find retardation of the train.


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Answer 1

Answer:

I won't spam.(θ‿θ)(θ‿θ). the answer is. 5 m/s^2

Step-by-step explanation:

by using the third equation of motion we can easily get__

v^2 = u^2 + 2as

(10)^2 = (40)^2 + (2)(a)(240)

100 = 2500 + 480a

(100)-(2500) = 480a

-2400 = 480a

-2400/480 = a

= -5m/s^2

acceleration would be -5m/s^2

retardation would be 5m/s^2

Answer 2

Friends this is my answer

I think it may help you

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