Question

a train is moving at a speed of 50m/s and reduces it's speed to 10m/s by covering a distance of 240m then find retardation of the train why ?

Given
small initial velocity = 50m/s
initial velocity=50m/s

final velocity = 10m\s
finalve locity=10mins

distance = 240 m distance=240m

Solution
{v}^{2} = {u}^{2} + 2as⟶v
2
=u
2
+2as

{10}^{2} = {20}^{2} + 2 × a × 240⟶10
2
=20
2
+2×a×240

100 = 2500 + 480a⟶100=2500+480a

100-2500 = 480a⟶100−2500=480a

-2400 = 480a⟶−2400=480a
a = -2400÷480
- 5 m/s​

Answer 1

hope it is helpful to you dear friend

Answer 2

Answer:

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