Question

A train is moving at a speed of 50m/s and reduces its speed to 10m/s by covering a distance of 240m then find the retardation of the train.

Answer 1

Explanation:

Initial velocity u=30m/s

Final velocity, v=10m/s

Distance traveled, s=240m

2 −u\2

=2as where 'a' is acceleration

100−900=2as

a= 2×240

−800

=− 6

10 m/s

2F=ma=−m

6 10

=1.125a ′

=1.125a=1.125×

6−10

=−1.875m/s

2

New distance traveled when v

=0 v 2−u

2=2a

′s

′0−900=2×(−1.875)×s

s =

2×1.875

900

=240m

___________________________________

you can take help from picture ♥

___________________________________