A train is moving at a velocity of 25 ms-1. It is brought to rest by applying the [3]
brakes which produces a uniform retardation of 0.5 ms-2. Calculate
(i) the velocity of the train after 10 s
(ii) If the mass of the train is 20000 kg then calculate the force required to stop the train
Answers
Answered by
5
Answer:
(i) So, we have t = 10 s
a = - 0.5 m/s² and u = 25 m/s
⇒v = u + at
⇒v = 25 + (-0.5)(10)
⇒v = 25 - 5 = 20 m/s
Speed of train after 10 s is 20 m/s
(ii) Since we know that,
⇒F = ma
Where we have m = 20,000 kg and a = 0.5 m/s²
⇒So, F = (20,000)(-0.5) kg m/s²
⇒F = - 10,000 N
Negative sign shows that force will be applied against direction of motion.
Force required to stop train is 10,000 N.
Answered by
2
by using 1st equation of motion
v=u+at
v=25m/s
a=0.5m/s^2
t=10sec
v=25+(-0.5×10)
25-5=20m/s
ii) F=ma
F=20000×0.5
10000N
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