Physics, asked by jk41338, 11 months ago

A train is moving at a velocity of 25 ms-1. It is brought to rest by applying the [3]
brakes which produces a uniform retardation of 0.5 ms-2. Calculate
(i) the velocity of the train after 10 s
(ii) If the mass of the train is 20000 kg then calculate the force required to stop the train

Answers

Answered by Anonymous
5

Answer:

(i) So, we have t = 10 s

a = - 0.5 m/s² and u = 25 m/s

⇒v = u + at

⇒v = 25 + (-0.5)(10)

⇒v = 25 - 5 = 20 m/s

Speed of train after 10 s is 20 m/s

(ii) Since we know that,

⇒F = ma

Where we have m = 20,000 kg and a = 0.5 m/s²

⇒So, F = (20,000)(-0.5) kg m/s²

⇒F = - 10,000 N

Negative sign shows that force will be applied against direction of motion.

Force required to stop train is 10,000 N.

Answered by shivanshi77
2

by using 1st equation of motion

v=u+at

v=25m/s

a=0.5m/s^2

t=10sec

v=25+(-0.5×10)

25-5=20m/s

ii) F=ma

F=20000×0.5

10000N

Similar questions