Question

A train is moving at a velocity of 25m/s. It is brought to rest by applying the brakes which produces a uniform retardation of 0.5m/s. Find the time required to stop the train.​

Answer 1

Answer:-

Time required to stop the train is 50 s

Explanation :-

We have :-

→Initial velocity (u) = 25 m/s

→Uniform Retardation (-a) = 0.5 m/s²

So, acceleration (a) = -0.5 m/s²

→ It came to rest by applying brakes (v) = 0 m/s

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So,

By using first equation of motion.We can find the value of "t"

v = u + at

where,

v = final velocity

u = initial velocity

a = acceleration

t = time taken

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Substituting the values,

⇒0 = 25 + (-0.5) t

⇒25 = 0.5 t

⇒t = 25/0.5

⇒t = 25/(5/10)

⇒t = 25/(1/2)

⇒t = 25×2/1

t = 50 s

So, time taken required to stop the train is 50 s.