Question

A train is moving from rest moves with a uniform acceleration of 0.2m/s2 for 5 minutes. Calculate the final velocity and the distance travelled in this time. with steps

Answer 1

Answer:

Initial speed = 0

time taken = 5 min = 300 s

let final speed = v

then,

use kinematics equation ,

v = u + at

= 0 + 0.2 × 300 = 60 m/s

and distance travelled = S ( let )

use formula ,

S = ut + 1/2at²

= 0 + 1/2 × 0.2 × (300)²

=0.1 × 90000

=9000 m

= 9 km

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Answer 2

Explanation:

This is the answer

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