A train is moving from Station A to Station B with a speed of u km/hr. Then it returns from Station B to Station A at a speed of v km/hr. Find the average speed?
Answers
Answered by
0
Explanation:
Net displacement of the train in coming back to the first station is zero i.e. S=0 .
Average velocity V
avg
=
t
S
=0
Average speed of the train when in moving equal distances is given by ∣V∣
avg
=
v
1
+v
2
2v
1
v
2
⟹ ∣V∣
avg
=
40+60
2×40×60
=48 km/h
Similar questions