a train is moving on a circular curve of radius 1500m @ 66 km per hour.through what angle has it moved in 10secs
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Given : a circle with radius r = 1500 m
a train is moving on a circular curve at rate of 66km per hour
therefore speed = 66 km per hr = 66*1000 / 3600
=18.33 m per sec
1 sec the distance covered= 18.33 m
10 sec................................= 18.333*10= 183.33m
now as we know theta (i.e angle) = arc/ radius
= 183.33 / 1500 =0.122 radians is the required angle covered Answer
a train is moving on a circular curve at rate of 66km per hour
therefore speed = 66 km per hr = 66*1000 / 3600
=18.33 m per sec
1 sec the distance covered= 18.33 m
10 sec................................= 18.333*10= 183.33m
now as we know theta (i.e angle) = arc/ radius
= 183.33 / 1500 =0.122 radians is the required angle covered Answer
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speed. of train=66/5 km/h
= 66/5×5/18=66/18=22/6 m/s
distance covered in 10s=(22/6)×10=220/6m=110/3 m.
circumference of circular curve=2πr
2π×1500=3000π m.
agme made in 3000π m=360°
angle made in 1m=(360/3000π)°
angle made in 110/3m=(360/3000π)×(110/3)
calculation in pic...
hope I m right....
if yes....
mark as brainliest
= 66/5×5/18=66/18=22/6 m/s
distance covered in 10s=(22/6)×10=220/6m=110/3 m.
circumference of circular curve=2πr
2π×1500=3000π m.
agme made in 3000π m=360°
angle made in 1m=(360/3000π)°
angle made in 110/3m=(360/3000π)×(110/3)
calculation in pic...
hope I m right....
if yes....
mark as brainliest
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