Question

a train is moving with 72 km/h . brakes are applied on it . find the force generale by the breaks train stops after 90 seconds given mass of train. 200 tonnes | class 9 chapter force and laws of motion | please give answer ಥ‿ಥ​

Answer 1

Explanation:

Hey There,

Here, we have the following data:

Initial Velocity = u = 72 km/hr = 72 \times \frac{5}{18}72×

18

5

m/s = 20 m/s

Final Velocity = v = 0 m/s

Distance Covered = s = 50 m

Let the acceleration value be a.

From the equations of motion, we have:

\begin{gathered}v^2 = u^2 + 2as \\ \\ \\ \implies 0 = (20)^2 + 2a(50) \\ \\ \\ \implies -100a = 400 \\ \\ \\ \implies \boxed{a = -4 \, \, m / s^2}\end{gathered}

v

2

=u

2

+2as

⟹0=(20)

2

+2a(50)

⟹−100a=400

⟹

a=−4m/s

2

Thus, the acceleration is - 4 \textbf{m/$s^2$}m/s

2

hope it helps;)

Answer 2

Explanation:

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