Question

a train is moving with a intial velocity of 30m/sec the brake is applied and produce deacceleration 1.5m/sec . calculate time in which it will come to rest

Answer 1

u=30m/sec.
a=-1.5m/sec^2


use equation of motion
v=u+at
0=30-1.5t
-30=-1.5t

t=200 seconds

Answer 2

Hey... Good Morning... ☺️

Here is your answer mate:

Initial velocity = 30m/s
Final velocity = 0m/s
Acceleration = -1.5m/s (as the train comes to rest)

Using definition of acceleration (1st equation of motion)
v = u+ at
0 = 30+ (-1.5)(t)
1.5t = 30
t = 30/1.5
= 20

So, the time taken by the train to come to rest was 20 seconds.

✌️☺️