Question

A train is moving with a speed of 20m/s. After applying brakes, it stopped in 10sec.
Calculate the retardation and distance travelled in this time .

Answer 1

Heya!

→ As the train is moving with speed 20m/s
That means it's initial speed is 20m/s

→ And it is stated that it stopped after a retardation that means it's final speed is 0

u = 20m/s
v = 0
a = ?
t = 10sec

Here,
u = initial speed
v = final speed
a = retardation( negative of acceleration)
t = time

So, among 3 equations of motion we will first equation of motion to find retardation.

v = u + at
0 = 20 + (-a)(10)
10a = 20
a = 2 m/s²

So, retardation produced is 2m/s²

Now in order to find the distance travelled we will use second equation of motion as per data available in the question.

s = ut + 1/2 at²
s = 20(10) + 1/2 (2) (10)²
s = 200 + 100
s = 300m

#Shati
#Brainly benefactor

Answer 2

Answer:

here is the answer given by Saksham sahu please like but don't mark as brainlest because I have copied from above

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