Question

a train is moving with a speed of 40km/h at 10.00am and 50 kmph at 10.02 am.assuming that acceleration is constant, find the average speed

Answer 1

u = 40 kmph
v = 50 kmph
t = 2 min = 1/30 h

a = (v-u)/t = 300 km/h^2
Distance travelled =(v^2 - u^2)/2a = 1.5 km

Average speed = 1.5km / (1/30 h) = 1.5×30 = 45 km/h

Answer 2

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u = 40 kmph

v = 50 kmph

t = 2 min = 1/30 h

a = (v-u)/t = 300 km/h^2

Distance travelled =(v^2 - u^2)/2a = 1.5 km

Average speed = 1.5km / (1/30 h) = 1.5×30 = 45 km/h

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