A train is moving with a velocity 400m/s. With the application of brakes a retardation of 10m/s^2 is produced. Calculate the following: 1)After how much time it will stop?
2)How much distance will it travel before it stops?
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Answered by
11
1) 40 s (v=u+at)
2)8000m (v^2=u^2+2aS)
2)8000m (v^2=u^2+2aS)
Answered by
22
The time taken to stop is 40 second
The distance travelled before it stops is 8000m
The distance travelled before it stops is 8000m
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