A train is moving with a velocity of 10m/s. It attains an acceleration of 4m/s after 5 seconds. Find the distance covered by the train at that time.
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Answered by
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Given that:
- A train is moving with a velocity of 10 m/s.
- It attains an acceleration of 4 m/s² after 5 seconds.
To Find:
- The distance covered by the train at that time.
First equation of motion,
- v = u + at
Where,
- v = Final velocity
- u = Initial velocity = 10 m/s
- a = Acceleration = 4 m/s²
- t = Time = 5 seconds
Finding the final velocity:
⟶ v = 10 + (4 × 5)
⟶ v = 10 + 20
⟶ v = 30
∴ Final velocity = 30 m/s
Second equation of motion,
- s = ut + (at²)/2
Where,
- s = Displacement
- v = Final velocity = 30 m/s
- u = Initial velocity = 10 m/s
- a = Acceleration = 4 m/s²
- t = Time = 5 seconds
Finding the distance covered by the train:
⟶ s = (10 × 5) + (4 × 5²)/2
⟶ s = 50 + (2 × 25)
⟶ s = 50 + 50
⟶ s = 100
Hence,
- The distance covered by the train at that time is 100 m.
Answered by
114
Answer:
Given :-
- A train is moving with a velocity of 10 m/s.
- It attains an acceleration of 4 m/s² after 5 seconds.
To Find :-
- What is the distance covered by the train at that time.
Formula Used :-
Second Equation Of Motion Formula :
where,
- u = Initial Velocity
- a = Acceleration
- t = Time
- s = Distance Covered
Solution :-
Given :
- Initial Velocity (u) = 10 m/s
- Time (t) = 5 seconds
- Acceleration (a) = 4 m/s²
According to the question by using the formula we get,
The distance covered by the train is 100 m .
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EXTRA INFORMATION :-
First Equation Of Motion Formula :
Third Equation Of Motion Formula :
where,
- s = Distance Covered (m)
- u = Initial Velocity (m/s)
- v = Final Velocity (m/s)
- a = Acceleration (m/s²)
- t = Time (s)
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