Question

A train is moving with a velocity of 18 km/h in 5 mins. Find its
acceleration and distance covered by the train

Answer 1

Explanation:

Given :-

• Initial Velocity u = 0
• Final Velocity v= 18 km/hr = 5 m/s
• Time t = 5 min = 300 sec
• Distance S = ?
• Acceleration a = ?

Using First equation of motion

• v = u + at
• 5 = 0 + a × 300
• a = 5 / 300 = 0.016 m/s²

Using Second equation of motion

• S = ut + 1/2 at²
• S = 0 × 300 + 1/2 × 0.016 × (300)²
• S = 1/2 × 0.016 × 300 × 300
• S = 750 m