Question

A train is moving with a velocity of 30 km/h due east. a car is moving with a velocity of 40 km/h due to north. what is the velocity of car as appeared to a passenger in the train?​

Answer 1

Answer:

50 km/h and angle is 37° west of North.

Explanation:

relative velocity of car w.r.t the train (let's take it as Vct)

Vct = Vc - Vt ( velocity of car - velocity of train)

given data

Vc = 40j

Vt = 30i

so Vct = 40j - 30i

so finding its magnitude |Vct| =

$\sqrt{(Vc)^2 +(Vt)^2}$

which gives you |Vct| = 50 km/h

And tanofangle with vertical is Vt/Vc

hence you get 37° with vertical i.e west of North.

Answer 2

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