A train is moving with a velocity of 72km/h. Breaks are applied and the train uniformly retards at the rate of 4m/s2.Find its velocity after 2 seconds?
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u = 72×1000/3600 =>20m/s
a=-4m/s^2
t=2secs
v=u+at
=20+(-4×2) =20-8
v=12m/s^2
Hope it helps u dear...!!☺☺
a=-4m/s^2
t=2secs
v=u+at
=20+(-4×2) =20-8
v=12m/s^2
Hope it helps u dear...!!☺☺
shivanyaaggraw:
okay
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