Question

A train is moving with an initial velocity of 108 km/h. The brakes are applied so as to produce a uniform acceleration of -1.5 m/s^2 . Calculate the time in which it will come to rest.

Answer 1

Given :

◆ u = 108 km/h

= 30m/s

$a \: = - 1.5 \: m \div {s}^{2}$

◆ v = 0 m/s

To find :

time taken , t = ?

equation used :

$v = u + at$

solution:

0 = 30 + ( -1.5 ) t

1.5t = 30

t = 30 / 1.5

t = 20 s

hope it helps

$\huge{\red{\ddot{\smile}}}$

Answer 2

$\huge\underline{\overline{\mid{\bold{\orange{ANSWER-}}\mid}}}$

⭐Given- ⭐

$u=108km/h=30m/s$

$a=-1.5m/s^2$

$v=0m/s$

⭐Find- ⭐

time{t}-?

⭐Solution- ⭐

equation of motion:-

$\boxed {a=\dfrac{v-u}{t}}$

$-1.5=\dfrac{0-108}{t}$

$t= \dfrac{30}{1.5}= 20s$