Question

A train is moving with an initial velocity of 30m/s. The brakes are
applied so as to produce a uniform acceleration of -1.5 m/s 2 .Calculate
the time in which it will come to rest.

solve this asap plss!!!

Answer 1

Answer:

20 seconds

Explanation:

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Answer 2

Given:

Initial velocity of train,u= 30 m/s

Final velocity of train,v= 0 m/s

(Since, train stops finally)

Acceleration of train,a= -1.5 m/s²

To Find:

Time taken by train to come at rest

Solution:

We know that,

• According to first equation of motion for constant acceleration,

$\purple{\boxed{\bf{v=u+at}}}$

where

v is final velocity

u is initial velocity

a is acceleration

t is time taken

$\rule{190}{1}$

Let the time taken by train to come at rest be 't'

So, on applying first equation of motion on train, we get

$\longrightarrow\rm{v=u+at}$

$\longrightarrow\rm{0=30+(-1.5)t}$

$\longrightarrow\rm{-30=-1.5t}$

$\longrightarrow\rm{-1.5t=-30}$

$\longrightarrow\rm{t=\dfrac{-30}{-1.5}}$

$\longrightarrow\rm\green{t=20\ s}$

Hence, the train will take 20 s to come at rest.