Question

A train is moving with the velocity of 45 km/hr. The driver applies
brake and the train gets stopped in 6 second. Now, calculate
retardation as well as distance covered by the train before coming to
the rest]. [Ans: a = 2.08 m/s2, s = 112.44 m]


PLEASE GIVE YOUR ANS IN A WRITTEN FORM

Answer 1

Answer:

use v=u+at. in case I

v=0,u=45km/h t=6second

0=45+6a

6a=-45

now change km/h to m/sby multiply 45into 5/18

and you will get acceleration in negative which is known as retardation

in case you have to use equation 2. s=ut+1/2at^2

Answer 2

Answer:

Ans: a = 2.08 m/s2, s = 112.44 m