Question

a train is moving with uniform acceleration the two ends of the train pass through a point on the track with velocities V1 and V2 .With what velocity the middle point of the train would pass through the same point​

Answer 1

Hello Mate❤

Answer:-.

$= > </u></strong><strong><u>[</u></strong><strong><u> \frac{</u></strong><strong><u>V</u></strong><strong><u> \frac{2}{1} + </u></strong><strong><u>V</u></strong><strong><u>\frac{2}{2} }{2} </u></strong><strong><u>]</u></strong><strong><u>$

Step-by-step explanation:

If the length of the train is 2s and its acceleration is a then,

We can say that

After moving a distance 2s its velocity changes from V1 to V2

So, apply the third equation of motion We get,

$v\frac{2}{2} = V\frac{2}{1} + 2a(2s)or \: we \: get \: 2a \\ = [\frac{V \frac{2}{2} - V \frac{2}{1} }{2s} ] \: \: \: \: \: \: \: \: \: \: \:..................(1)$

again applying the third equation of motion for a distance s (i.e mid point) taking V1 as the initial velocity

Suppose v be the velocity when mid point

passes then

$= > {V}^{2} = V\ \frac{2}{1} + 2a(s)$

putting value of 2a from the eqaution-1 .

we get,

$= > \sqrt[2]{ \frac{V \frac{2}{1} + V \frac{2}{2} } {2} }$

Have a nyc day

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