Question

a train is moving with velocity of 120 km per hour brakes are applied on the train and its velocity becomes 70 km per hour after travelling 100 M how much for the distance will it go before coming to rest

Answer 1

$\textbf {!!Hey Mate!! }$

your answer is ---

Given,

initial velocity u = 120kmph or 33.33m/s
& final velocity v = 70kmph or 19.44m/s

and , distance s = 100meter

so, according to formula

v^2 = u^2 + 2as

=> 19.44^2 = 33.33^2 + 2× a×100

=> 377.91 = 1110.89 + 200a

=> 377.91 - 1110.89 = 200a

=> -732.98 = 200a

=> a = - 732.98/200

=> a = -3.6649 ≈ - 3.66 m/s^2

now , when final velocity v become zero

the , distance is --

v^2 = u^2 + 2as

=> 0 = 1110.89 - 7.32s

=> s = 1110.89/7.32

=> s = 151.76 ≈ 151.8 meter


$\textbf { HOPE IT HELP YOU }$