Question

a train is moving with velocity of 60 kolilometersperhour brakes are applied to produce an accleration of 2meters per sec square .caluculate the time taken by for the train to come to rest and distance taken by train

Answer 1

Initial velocity =60km/h
So we convert it into m/s
60 will be multiplied by 5/18 or 1000/3600
So, Initial velocity will come = 16.66 m/s.
Retardation is given =2m/s2
Final velocity is 0 because it is given that train is going to rest.
U = 16.66 m/s
V = 0 m/s
A = 2m/s2

V = u + at
0 = 16.66 + 2t
- 2t = 16.66
T = 16.66/2
T = 8.33 seconds
So, time taken by train to come at rest is 8.33 seconds.