a train is moving with velocity of 72 k/h brakes are applied so that velocity becomes 36 k/h in 10 second. after that train acquires a velocity of 90 k/h in next seconds calculate acceleration in both cases.
Sunandit:
is this in next 10 sec
may be as it is written my assigment i had written same
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1st Case:-
u=72km/hr=20m/s
v=36km/hr=10m/s
t=10s
So,
a=(v-u)/t=(10-20)/10=(-1) m/s^2
2nd Case:-
u=36km/hr=10m/s
v=90km/hr=25m/s
So,
a=(v-u)/t=15/t m/s^2
I think t =10 s. So, a in 2nd case=1.5 m/s^2
HERE u is initial velocity, v is final velocity, t is time and a is acceleration.
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u=72km/hr=20m/s
v=36km/hr=10m/s
t=10s
So,
a=(v-u)/t=(10-20)/10=(-1) m/s^2
2nd Case:-
u=36km/hr=10m/s
v=90km/hr=25m/s
So,
a=(v-u)/t=15/t m/s^2
I think t =10 s. So, a in 2nd case=1.5 m/s^2
HERE u is initial velocity, v is final velocity, t is time and a is acceleration.
Plz mark it as brainliest..
what is the in second case
it is acceleration
thnx
plz mark it as brainliest..
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