Question

a train is running at 108 km/h is brought to a halt in 2min calculate the retardation production by the application of the brakes​

Answer 1

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Explanation:

Explanation :

Initial velocity of the train, u = 108 km/s = 30 m/s

It comes to rest. So, its final velocity is 0

Time taken, t = 2 min = 120 s

Retardation produced is given by :

Retardation produced is given by :

a={v-u}{/t}

a={0-30\ m/s}{/120\ s}

a=-0.25/m/s^2

The retardation produced by the brakes is .-0.25\ m/s^2

Now, using third equation of motion :

v^2-u^2=2as

s is the distance travelled

0^2-(30\ m/s)^2=2(-0.25\ m/s^2)s

s=1800\ m

Hence, this is the required solution.

Answer 2

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Explanation:

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