Question

a train is running at a constant speed of 90km/h on a straight track. a person standing at the top of a boggy moves in a direction of motion of the train such that he covers 1 m on the train each sec. the speed of the person w.r.t. ground is

Answer 1

90 km /s=90×5/18ms^2 so it should be justified that speed of the traini must be equal