A train is running at a speed of 90 kilometre and hour in how much time will it cross the distance between two station 7.5 km apart
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In this question it is given that A man who sits in the slower train cross the faster train it means faster train cross the man in 18second
Relative speed of faster train and man in the same direction = 58−30=2858−30=28kmph
So distance covered by faster train in 18 seconds =28kmph×18sec.28kmph×18sec.
=28×518×1828×518×18=140 metres.
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