Question

a train is running with velocity 3m/s.The rate of change of its velocity is 5m/s².Find its final velocity when it has covered a distance of 16m?​

Answer 1

Answer:

bro same isi type pe kar ans.mulzaiga....

The total distance travelled is =625m

Explanation:

The initial velocity is u=0ms−1

The acceleration is a=10ms−2

The time is t=5s

Apply the equation of motion

v=u+at

The velocity is

v=0+10⋅5=50ms−1

The distance travelled in the first 5s is

s=ut+12at2

=0⋅5+12⋅10⋅52=125m

The distance travelled in the following 10s is

s1=vt1=50⋅10=500m

The total distance travelled is

d=s+s1=125+500=625m

thank u broo...a ans.wrong hai han but esi type hogi...

τнänκ чöü♥█▬█ █ ▀█▀Rᴇᴅɪsᴄᴏᴠᴇʀɪɴɢ Lᴏᴠᴇ

Answer 2

Answer:

a = 5 m/s^2

s = 16 m

u = 3 m/s

v = ?

we know that, v^2 - u^2 = 2*a*s

                       v^2 - 3^2 = 2*5*16

                       v^2 -9 = 160

                       v^2 =169

                       v = 13 m/s