Question

a train is started from rest and accelerates uniformly at hundred minutes for 10 minutes it then maintain a constant velocity for 20 minute the break are then applied and the train is uniformly retarded and come to rest in 500 draw velocity time graph and use it to find the maximum velocity reached​

Answer 1

Explanation:

Let 'u' be initial velocity.

Let 'v' be final velocity.

The final velocity of the train is:

v=u+at

v = 0+ (100 × 10)

v = 1000 m/s

So, this is the maximum velocity of the train.

The distance covered is given by the

formula:

S= =

at²

Distance covered during uniform acceleration:

S₁ = at

$₁=¹ × 100 × 10² 2 X

S1 = 5000 m = 5 km

Distance covered during constant

velocity:

S₂ = v x t₂

S₂ = 1000 x 20

S₂ = 20000 m = 20 km

Distance covered during retardation:

Retardation = 200 m/min²

S3 = 1/at

S3 ¹× 200 × 5²

S3 = 2500 m = 2.5 km

Now, the total distance is:

S = S₁ + S₂ + S3

S = 5+20 +2.5

S = 27.5 km