Question

A train is starting from rest and attains a velocity of 48km/hr in 2 minutes. Find the distance travelled by the train.

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 0 m/s (As train starts from rest)

Final velocity, v = 48 km/h = 48 × 5/18 = 13.33 m/s

Time taken,t = 2 min = 2 × 60 = 120 seconds

To Find,

Distance covered, s = ?

At first we will find acceleration,

According to the 1st equation of motion,

We know that,

v = u + at

⇒ 13.33 = 0 + a × 120

⇒ 13.33 = 120a

⇒ 13.33/120 = a

⇒ a = 0.111083 m/s²

Here, the acceleration is 0.111083 m/s².

Now, the distance covered,

According to the 3rd equation of motion,

We know that,

v² - u² = 2as

⇒ (13.33)² - (0)² = 2 × 0.111083 × s

⇒ 177.6889 = 0.222166s

⇒ 177.6889/0.222166 = s

⇒ s = 799.8 m.

Hence, the distance covered by train is 799.8 m.

Answer 2

ɢɪᴠᴇɴ

• Initial velocity of train (u) = 0 m/s

• Final velocity of train (v) = 48km/h

48 ×5/18 = 40/3 m/s

• Time take (t) = 2 min. 2× 60 = 120 second

ᴛᴏ ғɪɴᴅ

• Distance (s) traveled by the train.

sᴏʟᴜᴛɪᴏɴs

Firstly , we have to find the acceleration of the train .

So, By using 1st equation of motion

➲ v = u + at

Putting all the values which is given above

40/3 = 0 + a ×120

40/3 = a × 120

a = 40/3×120

a = 1/9 m/s²

∴ The acceleration of the train is 160 m/s².

Now, we have to calculate the distance traveled by the train.

So, by using 2nd equation of motion

➲ s = ut + 1/2 at²

putting all the values which is given above

s = 0×120 + 1/2 × 1/9× 120²

s = 60 × 120/9

s = 800m

∴ The distance covered by train is 800 m.